Answer:
27/2
Step-by-step explanation:
Infinite Geometric Series =
where a₁ = first term and r = common ratio.
NOTE: Remember that the ratio in an infinite geometric sequence must be 0 < r < 1 or else it cannot be solved.
We can find out easily that a₁ = 9. Then, to find r, we must divide the second term by the first term which is 3/9 = 1/3 so r = 1/3,
Plugging in the values, = = .
Hope this helps!
~~DeanGD20
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Answers & Comments
Answer:
27/2
Step-by-step explanation:
Infinite Geometric Series =![\frac{a_1}{1-r} \frac{a_1}{1-r}](https://tex.z-dn.net/?f=%5Cfrac%7Ba_1%7D%7B1-r%7D)
where a₁ = first term and r = common ratio.
NOTE: Remember that the ratio in an infinite geometric sequence must be 0 < r < 1 or else it cannot be solved.
We can find out easily that a₁ = 9. Then, to find r, we must divide the second term by the first term which is 3/9 = 1/3 so r = 1/3,
Plugging in the values,
=
=
.
Hope this helps!
~~DeanGD20