Answer:
Sin A=4/root 13
sec^2A-tan^2A
=1 [ identitity]
Step-by-step explanation:
cotA=4/3
cotA=base/perpendicular
so, 4 is base and 3 is perpendicular
By Pythagoras Theorem,
AB^2+BC^2=AC^2
3^2+2^2=AC^2
9+4=AC^2
under root 13=AC
So, Sin A=4/root 13
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Answer:
Sin A=4/root 13
sec^2A-tan^2A
=1 [ identitity]
Step-by-step explanation:
cotA=4/3
cotA=base/perpendicular
so, 4 is base and 3 is perpendicular
By Pythagoras Theorem,
AB^2+BC^2=AC^2
3^2+2^2=AC^2
9+4=AC^2
under root 13=AC
So, Sin A=4/root 13
sec^2A-tan^2A
=1 [ identitity]
Hope you understood the answer ❤
like the answer
mark me as brainliast
Bye