The initial and the final positions of the object are 1 and 3 respectively. Hence apply the integration formula here with the limits.
b
∫
a
g
(
x
)
d
x
∫
a
b
g
(
x
)
d
x
= G(b) - G(a)
3
∫
1
v
(
t
)
)
d
t
∫
1
3
v
(
t
)
)
d
t
= v(3) - v(1)
3
∫
1
∫
1
3
v(t)=
3
∫
1
∫
1
3
-t2 +
3
∫
1
∫
1
3
5t
= -t3/3 + 5t2 /2
= [(-27/3-1/3)+(45/2 - 5/2)]
= -28/3 +40/3 =12/3
Displacement =4
I only use T E L E m g r a m.
b
∫
a
g
(
x
)
d
x
∫
a
b
g
(
x
)
d
x
= G(b) - G(a)
3
∫
1
v
(
t
)
)
d
t
∫
1
3
v
(
t
)
)
d
t
= v(3) - v(1)
3
∫
1
∫
1
3
v(t)=
3
∫
1
∫
1
3
-t2 +
3
∫
1
∫
1
3
5t
= -t3/3 + 5t2 /2
= [(-27/3-1/3)+(45/2 - 5/2)]
= -28/3 +40/3 =12/3
Displacement =4
I only use T E L E m g r a m.
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