3 consecutive positive integers are such that the sum of the the square of the first no. and the product of the other two numbers is 46. Find the integers.
Please give full answers with explanation.
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Please give full answers with explanation.
Thanks
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x^2+(x+1)(x+2)=46
x^2+x^2+3x+2=46
2x^2+3x-44=0
Find the roots of the equation by quadratic formula
a= 2 ,b= 3 ,c= -44
b^2-4ac= 9 + 352
b^2-4ac= 361



x1=( -3 + 19 )/ 4
x1= 4
x2=( -3 -19 ) / 4
x2= -5.5
They are integers 4,5,6
ur solution is here
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