Answer:

therefore,the zeros are

a=7, ,

Sum of the zeros

Product of the zeros

Verification:

Sum of the zeros

Product pf the zeros

Answer:

2/3  & -1/7

Step-by-step explanation:

Find the zeroes of the polynomial 7y^2 - 11/3 y - 2/3 by factorisation method and verify the relations between the zeroes and the coefficients of the polynomial.

7y² - 11y/3  - 2/3 = 0

=> 21y² - 11y - 2 = 0

=> 21y² + 3y - 14y - 2 = 0

=> 3y(7y + 1) - 2(7y + 1) = 0

=> (3y -2)(7y + 1) = 0

=> y = 2/3  or -1/7

Sum of roots = 2/3 - 1/7 =  11/21  =  -b/a = - (-11/3 )/7 = 11/21

Products of roots = (2/3)(-1/7) = - 2/21 = c/a =  (-2/3)/7 = - 2/21