Verify that 1 , -1 , -1/3 are the zeroes of the polynomial 3x³ -5x² - 11x - 3 and then verify the relationship between the zeroes and coefficients.
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p(x) = 3x^3 - 5x^2 -11x-3
p(x) = 3(1)^3 -5(1)^2-11(1)-3
= 3 -5-11-3
= 3 - 19
= -16
p(x) = -1
p(x) = 3(-1)^2 - 5( -1)^2 -11 (-1) -3
= -3 -5 +11 -3
= -11+11
= 0
p(x) = 1/3
p(x) = 3(1/3)^3 -5(1/3)2 -11(1/3) -3
= 3 (1/27) -5(1/9) -11/3 -3
= 3/27 -5/9 -11 -9/3
= 3/27 -5/9 -20/3
L.C.M OF 27,9 ,3 = 27
= 3/27×27 -5/9×27 -29/3×27
____________________
27
= 3 -15 - 261/27
= 3 -276/27
= -273/27
l hope it is right answer
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