Answer:
a. 3
Step-by-step explanation:
To solve this system of equations:
31x + 47y = 15
47x + 31y = 63
We can use the method of elimination. Multiplying the first equation by 47 and the second equation by -31, we get:
1457x + 2209y = 705
-1457x - 961y = -1953
Adding these two equations together, we get:
1248y = -1248
Dividing both sides by 1248, we get:
y = -1
Substituting y = -1 into either of the original equations, we get:
31x + 47(-1) = 15
31x - 47 = 15
31x = 62
x = 2
Therefore, x - y = 3.
So the answer is (a) 3.
I hope that helps!
On solving 31x+47y= 15 and 47x+31y = 63, then x-y= a) 3. b)-3. c) 1/3. d)-1/3.
47x+31y63 ---(i)
31 +47y 15(ii)
multiplying (i) by 31 and multiplying (ii) by 47 we
get
1457x+961y 1953 (iii)
1457x+2209y= 705 ---(iv)
subtracting (iv) from (iii) we get -1248y 1248
⇒y=-1 putting y=-1 in (i)
47x+31x-1= 63
47 94 ⇒ 47x=
x 2 and y = -1
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Answers & Comments
Answer:
a. 3
Step-by-step explanation:
To solve this system of equations:
31x + 47y = 15
47x + 31y = 63
We can use the method of elimination. Multiplying the first equation by 47 and the second equation by -31, we get:
1457x + 2209y = 705
-1457x - 961y = -1953
Adding these two equations together, we get:
1248y = -1248
Dividing both sides by 1248, we get:
y = -1
Substituting y = -1 into either of the original equations, we get:
31x + 47(-1) = 15
31x - 47 = 15
31x = 62
x = 2
Therefore, x - y = 3.
So the answer is (a) 3.
I hope that helps!
Verified answer
On solving 31x+47y= 15 and 47x+31y = 63, then x-y= a) 3. b)-3. c) 1/3. d)-1/3.
Step-by-step explanation:
47x+31y63 ---(i)
31 +47y 15(ii)
multiplying (i) by 31 and multiplying (ii) by 47 we
get
1457x+961y 1953 (iii)
1457x+2209y= 705 ---(iv)
subtracting (iv) from (iii) we get -1248y 1248
⇒y=-1 putting y=-1 in (i)
47x+31x-1= 63
47 94 ⇒ 47x=
x 2 and y = -1