To rationalize the denominator of 1/(√3 - √2 + √5), we need to multiply both the numerator and denominator by the conjugate of the denominator, which is (√3 + √2 + √5).
Therefore, we have:
1 / (√3 - √2 + √5) = 1 / (√3 - √2 + √5) × (√3 + √2 + √5) / (√3 + √2 + √5)
Simplifying the numerator using the distributive property, we get:
= (√3 + √2 + √5) / [(√3)² - (√2)² + (√5)²]
= (√3 + √2 + √5) / (3 - 2 + 5)
= (√3 + √2 + √5) / 6
Therefore, the rationalized form of 1/(√3 - √2 + √5) is (√3 + √2 + √5)/6.
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I hope this helps Cutiepie ❤️!. Please let me know if you have any other questions.
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Answers & Comments
To rationalize the denominator of 1/(√3 - √2 + √5), we need to multiply both the numerator and denominator by the conjugate of the denominator, which is (√3 + √2 + √5).
Therefore, we have:
1 / (√3 - √2 + √5) = 1 / (√3 - √2 + √5) × (√3 + √2 + √5) / (√3 + √2 + √5)
Simplifying the numerator using the distributive property, we get:
= (√3 + √2 + √5) / [(√3)² - (√2)² + (√5)²]
= (√3 + √2 + √5) / (3 - 2 + 5)
= (√3 + √2 + √5) / 6
Therefore, the rationalized form of 1/(√3 - √2 + √5) is (√3 + √2 + √5)/6.
__________________________________
I hope this helps Cutiepie ❤️!. Please let me know if you have any other questions.
__________________________________