Answer:
the answer is not varIiable
The values are:
a = 5
b = -2
Step-by-step explanation:
Given that,
\frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} - \sqrt{2} } = a - b \sqrt{6}
by conjugating the given equation, we get
\frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} - \sqrt{2} } * \frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} + \sqrt{2}}
= \frac{(\sqrt{3} + \sqrt{2})^2 }{(\sqrt{3})^2 - (\sqrt{2})^2 }
= \frac{3 + 2 + 2\sqrt{3} \sqrt{2} }{3 - 2}
= \frac{5+2\sqrt{6}}{1}
So,
\frac{5+2\sqrt{6}}{1} = a - b√6
∵ a = 5
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Answers & Comments
Answer:
the answer is not varIiable
The values are:
a = 5
b = -2
Step-by-step explanation:
Given that,
\frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} - \sqrt{2} } = a - b \sqrt{6}
by conjugating the given equation, we get
\frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} - \sqrt{2} } * \frac{\sqrt{3} + \sqrt{2} }{\sqrt{3} + \sqrt{2}}
= \frac{(\sqrt{3} + \sqrt{2})^2 }{(\sqrt{3})^2 - (\sqrt{2})^2 }
= \frac{3 + 2 + 2\sqrt{3} \sqrt{2} }{3 - 2}
= \frac{5+2\sqrt{6}}{1}
So,
\frac{5+2\sqrt{6}}{1} = a - b√6
∵ a = 5
b = -2
Step-by-step explanation:
hope it is helpful and please mark me as brainlist pleaseee