3) (15p - 16r +213) - (6p - 9r+285)pa help po. Created by rochellemaevelasquez. Math

Answer:PROBLEM:3) (15p - 16r +213) - (6p - 9r+285)ANSWER:SOLUTION:1.Simplify or factorize↓Remove the parentheses for addition or subtration15p - 16r +213 - 6p + 9r - 285[/tex]↓Reorder and gather like terms↓Collect coefficient of like terms↓Calculate the sum or difference↓Calculate the sum or difference↓Calculate the sum or differenceSo the answer is 9p - 7r - 72

3) (15p - 16r +213) - (6p - 9r+285)pa help po...

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Answer:

PROBLEM:

3) (15p - 16r +213) - (6p - 9r+285)

ANSWER:

$9p - 7r - 72$

SOLUTION:

1.Simplify or factorize

$(15p - 16r +213) - (6p - 9r+285)$

↓Remove the parentheses for addition or subtration

15p - 16r +213 - 6p + 9r - 285[/tex]

↓Reorder and gather like terms

$(15p - 6p) + ( - 16r + 9r) + (213 - 285)$

↓Collect coefficient of like terms

$(15 - 6 ) \times p + ( - 16 + 9 ) \times r + (213 - 285 )$

↓Calculate the sum or difference

$9p + ( - 16 + 9 ) \times r + (213 - 285)$

↓Calculate the sum or difference

$9p - 7r + (213 - 285)$

↓Calculate the sum or difference

$9p - 7r - 72$

So the answer is 9p - 7r - 72

rueljohnreynonato

(9p² -7r² -72)

SOLUTION:

$15p - 6p = 9 {p}^{2}$

$- 16r - (- 9r) = - 7 {r}^{2}$

$213 - 285 = - 72$

rochellemaevelasquez pano mo po nakuha ung -72

rueljohnreynonato subtract niyo po yung 213 subtracted to 285 = -72

rueljohnreynonato pa thanks po then 5star thank you

rochellemaevelasquez pano mo po nakuha ung 213 and 285?

rueljohnreynonato nasa unahan po kase siya, nilagayan sila ng parenthesis kase may negative at positive numbers so yung solution tignan niyo nalang po sa ilalim.

rochellemaevelasquez ahh ok po thank you po

rueljohnreynonato pa thanks na rin po yung HEART button

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(9p² -7r² -72)

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