Verified answer

Answer:

So, the result of dividing 2y^4 + y^3 + 4y^2 + 2y + 3 by y^2 + y + 1 is 2y^2 - y + 3 with a remainder of -y.

Step-by-step explanation:

2y^2 - y + 3

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y^2 + y + 1 | 2y^4 + y^3 + 4y^2 + 2y + 3

- (2y^4 + 2y^3 + 2y^2)

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- y^3 + 2y + 3

- (-y^3 - y^2 - y)

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3y^2 + 2y + 3

- (3y^2 + 3y + 3)

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-y