[tex]given \\ 2x + y = 3 > 1 \\ 3x - y = 8 > 2[/tex]
[tex]1+2=5x=−5 \\
x=−1 \\
substituting \: value \: of \: x \: \\
in \: equation \: 1 \\ [/tex]
[tex]2×−1+y=3 \\
−2+y=3 \\
y=3+2=5
[/tex]
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[tex]given \\ 2x + y = 3 > 1 \\ 3x - y = 8 > 2[/tex]
[tex]1+2=5x=−5 \\
x=−1 \\
substituting \: value \: of \: x \: \\
in \: equation \: 1 \\ [/tex]
[tex]2×−1+y=3 \\
−2+y=3 \\
y=3+2=5
[/tex]
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