=> d( 2x + logx)
using u + v rule
we get
d(2x) + d( logx)
=> 2 + 1/x
=> (2x+1)/x
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=> d( 2x + logx)
using u + v rule
we get
d(2x) + d( logx)
=> 2 + 1/x
=> (2x+1)/x