Answer:
Step-by-step explanation:
Given:
We have been given a quadratic polynomial 2x²-x-3.
Solution:
We need to factorise this polynomial using the method of splitting the middle term.
Here, we need two such numbers whose product is -6 and sum is -1.
Two such numbers are -3 and +2.
Now, substituting values in 2x²-x-3, we have
=> 2x² + 2x - 3x - 3
=> 2x( x + 1 ) -3( x + 1 )
=> ( x + 1 ) ( 2x - 3 )
Either ( x + 1 ) = 0 or ( 2x - 3 ) = 0
x + 1 = 0
=> x = -1
2x - 3 = 0
=> 2x = 3
=> x = 3/2
Either x = -1 or x = 3/2.
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Verified answer
Answer:
Step-by-step explanation:
Given:
We have been given a quadratic polynomial 2x²-x-3.
Solution:
We need to factorise this polynomial using the method of splitting the middle term.
Here, we need two such numbers whose product is -6 and sum is -1.
Two such numbers are -3 and +2.
Now, substituting values in 2x²-x-3, we have
=> 2x² + 2x - 3x - 3
=> 2x( x + 1 ) -3( x + 1 )
=> ( x + 1 ) ( 2x - 3 )
Either ( x + 1 ) = 0 or ( 2x - 3 ) = 0
x + 1 = 0
=> x = -1
2x - 3 = 0
=> 2x = 3
=> x = 3/2
Either x = -1 or x = 3/2.