Answer:
Given quadratic polynomial is 2s2−(1+22)s+2
=2s2−s−22s+2
=s(2s−1)−2(2s−1)
=(2s−1)(s−2)
s=21 and s=2
The relationship between the zeroes and their coefficient,
Sum of the zeroes=−coefficient of s2coefficient of s
=−(2−(1+22))
=21+22
Also sum of the zeroes=21+2
2+575
68
58
896
6+7
0=7
thanks you
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Answers & Comments
Answer:
Given quadratic polynomial is 2s2−(1+22)s+2
=2s2−s−22s+2
=s(2s−1)−2(2s−1)
=(2s−1)(s−2)
s=21 and s=2
The relationship between the zeroes and their coefficient,
Sum of the zeroes=−coefficient of s2coefficient of s
=−(2−(1+22))
=21+22
Also sum of the zeroes=21+2
=21+22
Answer:
2+575
68
58
896
6+7
0=7
thanks you