Answer:
(2x/3y−3y/2x)
2
= (
3y
2x
)
−2×
2y
×
+(
){(a−b)
=a
−2ab+b
}
=
9y
4x
−2+
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Answers & Comments
Answer:
(2x/3y−3y/2x)
2
= (
3y
2x
)
2
−2×
2y
2x
×
2x
3y
+(
2x
3y
){(a−b)
2
=a
2
−2ab+b
2
}
=
9y
2
4x
2
−2+
4x
2
9y
2