We have,

2x + y = 7 (1)

3x + 2y = 12 (2)

Multiply equation (1) by 2, we get:

2(2x+y) = 2(7)

⇒

4x+2y = 14 (3)

Subtract (2) from (3) we get:

x = 2

y = 3

Thus, the solution for the given pair of linear equation is (2,3).

Answer:

1 Multiply the 1st row by 2.

​

6x+4y=24

2x−3y=1

​

2 Multiply the 2nd row by 3.

​

6x+4y=24

6x−9y=3

​

3 Subtract the 2nd row from the 1st row.

13y=21

13y=21

4 Solve for y in the above equation.

y=

13

21

​

5 Substitute y

13

21

​

 into any of the two equations above

Let's pick the first equation 6x+4y=246x+4y=24.

6x+4\times \frac{21}{13}=24

6x+4×

13

21

​

=24

6 Solve for xx in the above equation.

x=\frac{38}{13}

x=

13

38

​

7 Therefore,

\begin{aligned}&x=\frac{38}{13}\\&y=\frac{21}{13}\end{aligned}

​

x=

13

38

​

y=

13

21

​

​

Done