x²/x-3=x+2/2x-5 rational equation solve
Multiply all terms by x and cancel:
x² + −3x = xx + xx + −5x
x² - 3x = 2x² − 5x (Simplify both sides of the equation)
x² − 3x − (2x² − 5x) = 2x² − 5x − (2x² - 5x) (Subtract 2x^2-5x from both sides)
−x²+ 2x = 0
x (−x + 2) = 0 (Factor left side of equation)
x = 0 or −x + 2 = 0 (Set factors equal to 0)
x = 0 or x = 2
Check answers. (Plug them in to make sure they work.)
x = 0 (Doesn't work in original equation)
x = 2 (Works in original equation)
The answer is
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Answers & Comments
x²/x-3=x+2/2x-5 rational equation solve
Multiply all terms by x and cancel:
x² + −3x = xx + xx + −5x
x² - 3x = 2x² − 5x (Simplify both sides of the equation)
x² − 3x − (2x² − 5x) = 2x² − 5x − (2x² - 5x) (Subtract 2x^2-5x from both sides)
−x²+ 2x = 0
x (−x + 2) = 0 (Factor left side of equation)
x = 0 or −x + 2 = 0 (Set factors equal to 0)
x = 0 or x = 2
Check answers. (Plug them in to make sure they work.)
x = 0 (Doesn't work in original equation)
x = 2 (Works in original equation)
The answer is![\LARGE\bold\green{2} \LARGE\bold\green{2}](https://tex.z-dn.net/?f=%5CLARGE%5Cbold%5Cgreen%7B2%7D)