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Answer:

Question :-

2x - 3y + 6 = 0 and 2x + 3y - 18 = 0 solve by elimination method.

2x - 3y + 6 = 0

➾ 2x - 3y = - 6 . . . . . (1)

2x + 3y - 18 = 0

➔ 2x + 3y = 18 . . . . . (2)

Multiply equation (1) by 1, (2) by 1 , we get

2x - 3y = - 6 . . . . . (3)

2x + 3y = 18 . . . . . (4)

Adding (3) and (4) we get,

2x - 3y = - 6

2x + 3y = 18

(-) (-) (-)

____________

- 6y = - 24

y = - 24/- 6

y = 4

Substituting the value of y = 4 in equation (1) we get,

2x - 3y = - 6

➩ 2x - 3(4) = - 6

➩ 2x - 12 = - 6

➩ 2x = - 6 + 12

➩ 2x = 6

➩ x = 6/2

➩ x = 3

∴ The value of x = 3, y = 4 is the solution of the system of the given equations.

Step-by-step explanation:

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