2x – 1)(x + 3) = 0
A. a = 5, b = 2, c = -3
B. a = 2, b = 5, c = 3
C. a = 2, b = 5, c = -3
D. a = 5, b = 2, c = 3
10x^2 – 3x – 20 = 0
A. a = 10, b = -3, c = -20
B. a = 10, b = 3, c = 20
C. a = 10, b = -3, c = 20
D. a = -10, b = -3, c = -20
6x^2 + 2 = 0
A. a = 6, b = -2, c = 0
B. a = 6, b = 0, c = 2
C. a = 6, b = 0, c = -2
D. a = 6, b = 2, c = 0
Answers & Comments
Answer:
c
b
d
Step-by-step explanation:
2x – 1)(x + 3) = 0
A. a = 5, b = 2, c = -3
B. a = 2, b = 5, c = 3
C. a = 2, b = 5, c = -3
D. a = 5, b = 2, c = 3
10x^2 – 3x – 20 = 0
A. a = 10, b = -3, c = -20
B. a = 10, b = 3, c = 20
C. a = 10, b = -3, c = 20
D. a = -10, b = -3, c = -20
6x^2 + 2 = 0
A. a = 6, b = -2, c = 0
B. a = 6, b = 0, c = 2
C. a = 6, b = 0, c = -2
D. a = 6, b = 2, c = 0
Answer:
1. c
2. a
3. a
Step-by-step explanation:
first we need to multiply it (2x – 1)(x + 3) = 0
remember the FOIL method; F-first term (2x)(x), O-outer term (2x)(3), I-inner term (-1)(x), ang L-last term (-1)(3). Multiply the terms, we have 2x^2 +6x-x-3= 2x^2+5x-3
remember the standard form of writing quartic equation. ax^2+bx+c=0.. so a=2, b=5 and C=-3
10x^2 – 3x – 20 = 0
just follow the standard form in order to identify a, b and c
6x^2 + 2 = 0
follow the standard form. since their is no value of x, so b=0