(2w-5)(w-3)=55
solution po☝
2w²-11w-15=55
solution po☝
2w²-11-40=0
solution po☝
(2w+5)w-8)=0
solution po☝
w=8 or w =-5/2
solution po☝
solution po☝
2w²-11w-15=55
solution po☝
2w²-11-40=0
solution po☝
(2w+5)w-8)=0
solution po☝
w=8 or w =-5/2
solution po☝
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Answer:
2w2−11w+15=55
Step 2: Subtract 55 from both sides.
2w2−11w+15−55=55−55
2w2−11w+15−55=55−552w2−11w−40=0
Step 3: Factor left side of equation.
(2w+5)(w−8)=0
Step 4: Set factors equal to 0.
2w+5=0 or w−8=0
w=8
2w2−11w−15=55
Step 1: Subtract 55 from both sides.
2w2−11w−15−55=55−55
2w2−11w−70=0
For this equation: a=2, b=-11, c=-70
2w2+−11w+−70=0
Step 2: Use quadratic formula with a=2, b=-11, c=-70.
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W= −b±√b2−4ac
2a
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w= −(−11)±√(−11)2−4(2)(−70)
2(2)