Answer:

(-b - 1) • (2b + 5)

Step-by-step explanation:

(1): "b2"   was replaced by   "b^2".  

((0 -  2b2) -  7b) -  5

-2b2 - 7b - 5  =   -1 • (2b2 + 7b + 5)

Factoring  2b2 + 7b + 5  

The first term is,  2b2  its coefficient is  2 .

The middle term is,  +7b  its coefficient is  7 .

The last term, "the constant", is  +5  

Step-1 : Multiply the coefficient of the first term by the constant   2 • 5 = 10  

Step-2 : Find two factors of  10  whose sum equals the coefficient of the middle term, which is   7 .

    -10    +    -1    =    -11  

    -5    +    -2    =    -7  

    -2    +    -5    =    -7  

    -1    +    -10    =    -11  

    1    +    10    =    11  

    2    +    5    =    7    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  2  and  5  

                   2b2 + 2b + 5b + 5

Step-4 : Add up the first 2 terms, pulling out like factors :

                  2b • (b+1)

            Add up the last 2 terms, pulling out common factors :

                  5 • (b+1)

Step-5 : Add up the four terms of step 4 :

                  (2b+5)  •  (b+1)

Answer:

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Step-by-step explanation:

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