Answer:
2(a²+b²+c²)
As,
(a+b+c)²= a²+b²+c²+2ab+2bc+2ac
(a+b+c)²-2(ab+bc+ac) = a²+b²+c²
Multiply both sides by 2 then
2(a+b+c)²-2(ab+bc+ac) = 2(a²+b²+c²)
so,
the value of 2(a²+b²+c²) = 2(a+b+c)²-2(ab+bc+ac)
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Answer:
2(a²+b²+c²)
As,
(a+b+c)²= a²+b²+c²+2ab+2bc+2ac
(a+b+c)²-2(ab+bc+ac) = a²+b²+c²
Multiply both sides by 2 then
2(a+b+c)²-2(ab+bc+ac) = 2(a²+b²+c²)
so,
the value of 2(a²+b²+c²) = 2(a+b+c)²-2(ab+bc+ac)
Mark me as the brilliant answer plz