29. Two pipes can fill a cistern with water in 4 and 6 hours respectively. If the first pipe be opened first and the pipes be opened alternately one at a time for 1 hour each, in how many hours will the cistern filled up?
please answer fast!! All kinds of irrevalent answers will be reported!
please answer fast!! All kinds of irrevalent answers will be reported!
Answers & Comments
Step-by-step explanation:
good question it was
1+2+3+3+4+5+6+7+8+9-10 = 0987
Answer:
Let A take "X" hours to fill the tank
So "B" takes (X+6) hours to fill the tank.
In 1-day both A and B can fill=1/X+1/(X+6)= 1/4 hours.
On simplication we get,
=4(X+6) + 4X= X(X+6)
=4X+24+4X= X^2+6X
=X^2-2X-24=0
=(X-6) (X+4)= 0
So X-6 or -4
Neglecting the negative value "X"= 6
So pipe -A can fill the cistern in 6- hours.
Step-by-step explanation:
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