Answer:
Step-by-step explanation:
w = 16 in
l = 9 in
x = the uniform width of the frame, x>0 (the width can not be negative number)
A1 = 84 in^2 area of the frame
A = the area of photograph and frame
the width of the photograph and frame is: 16 + 2x
the length of the photograph and frame is: 9 + 2x
A = (16 + 2x)(9 + 2x)
the area of the photograph is = A - A1
A - A1 = l*w
(16 + 2x)(9 + 2x) - 84 = 16*9
simplifying we get the quadratic equation:
2x^2 - 25x - 42 = 0
by solving we find:
x = 1.5 in
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Answers & Comments
Answer:
Step-by-step explanation:
w = 16 in
l = 9 in
x = the uniform width of the frame, x>0 (the width can not be negative number)
A1 = 84 in^2 area of the frame
A = the area of photograph and frame
the width of the photograph and frame is: 16 + 2x
the length of the photograph and frame is: 9 + 2x
A = (16 + 2x)(9 + 2x)
the area of the photograph is = A - A1
A - A1 = l*w
(16 + 2x)(9 + 2x) - 84 = 16*9
simplifying we get the quadratic equation:
2x^2 - 25x - 42 = 0
by solving we find:
x = 1.5 in