1. 27 y³ — 125
=3³y³-5³
=(3y^3)-5
=(3y-5)(3y^2)+3y×5+5²)
=(3y-5)×(9y+15y+25)
2. 125x³ + 1000
=125(x^3+8)
=125(x+2)(x²-2x+4)
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Answers & Comments
1. 27 y³ — 125
=3³y³-5³
=(3y^3)-5
=(3y-5)(3y^2)+3y×5+5²)
=(3y-5)×(9y+15y+25)
2. 125x³ + 1000
=125(x^3+8)
=125(x+2)(x²-2x+4)
#CarryOnLearning