The length of a garden is 4m more than twice its width and its area is 38m². Which of the following equations
represents the given situation?
The Area of rectangle is measured by multiplying its width and length. In mathematical representation,
A = L × W
Let x be the width, hence, W = x
Length is 4 meters more than twice the Width,
hence, L = 2x + 4
It is stated that the Area is equal to 38 m²
Substituting all of it, we get,
38 = (2x + 4) (x)
38 = 2x(x) + 4(x)
38 = 2x² + 4x
0 = 2x² + 4x - 38
2x² + 4x - 38 = 0
#CarryOnLearning
c
Step-by-step explanation:
because 2x2=4 and 19x2=38 but im not sure if my ans is correct...
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PROBLEM
The length of a garden is 4m more than twice its width and its area is 38m². Which of the following equations
represents the given situation?
ANSWER
2x² + 4x - 38 = 0
SOLUTION
The Area of rectangle is measured by multiplying its width and length. In mathematical representation,
A = L × W
Let x be the width, hence, W = x
Length is 4 meters more than twice the Width,
hence, L = 2x + 4
It is stated that the Area is equal to 38 m²
Substituting all of it, we get,
A = L × W
38 = (2x + 4) (x)
38 = 2x(x) + 4(x)
38 = 2x² + 4x
0 = 2x² + 4x - 38
2x² + 4x - 38 = 0
#CarryOnLearning
c
Step-by-step explanation:
because 2x2=4 and 19x2=38 but im not sure if my ans is correct...