26. A simple Atwood machine with two masses 3 kg and 2 kg connected by a light string X passing passing over frictionless pulley, a suspended with a spring balance as shown in figure. The reading of spring balance is
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Explanation:
Given,
Masses M
1
=300g,M
2
=600g
So,
T−(M
1
g+M
1
a)=0
T=M
1
g+M
1
a......1
Similarly,
T=m
2
−M
2
g.....2
By equating equation 1 and 2 then we get,
M
1
g+M
1
a+M
2
a−M
2
g=0
a(M
1
+M
2
)=g(M
2
−M
1
)
a=
(M
1
+M
2
)
g(M
2
−M
1
)
9.8(
0.6+0.3
0.6−0.3
)
=3.266m/s
2
a)
At t=2s
Initial velocity u=0
Acceleration =3.266m/s
2
So, Distance traveled by the body is:
s=ut+
2
1
at
2
=0+
2
1
3.266×2
2
=6.5m