A box of chocolates contains 4 milk chocolates, 2 dark chocolates and 6 white chocolates. Trixie randomly chooses a chocolate, eats it and then randomly chooses another chocolate. What is the probability that Trixie choose a milk chocolate and then a dark chocolate?
A. 2/25
B. 4/45
C. 3/5
D. 4/25
may solution po sana
A. 2/25
B. 4/45
C. 3/5
D. 4/25
may solution po sana
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4 milk
2 dark
6 white
4 + 2 + 6 = 12 chocolates
there are 4 milk chocolates
therefore:
4/12 = 1/3 is the probability of trixie picking milk chocolate..
now she already eat one choclate, then there are 11 chocolates left..
second chocolate must be dark.. total number of dark chocolate is 2..
2/11 is the probability of trixie picking dark chocolate after eating one chocolate..
multiply the probabilities
(1/3)(2/11)
= 2/33
= 0.0606
= 0.06
0.06 = 6/10 = 3/5