Answer:
[tex]\mathrm{\left(\frac{2}{3}+\frac{1}{5}n^2\right)\left(\frac{2}{3}-\frac{1}{5}n^2\right)}[/tex]
Step-by-step explanation:
[tex]\mathrm{\frac{4}{9}-\frac{1}{25}n^4}\\\\\mathrm{=\left(\frac{2}{3}\right)^2-\left(\frac{1}{5}n^2\right)^2}\\\\\mathrm{=\left(\frac{2}{3}+\frac{1}{5}n^2\right)\left(\frac{2}{3}-\frac{1}{5}n^2\right)}[/tex]
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Verified answer
Answer:
[tex]\mathrm{\left(\frac{2}{3}+\frac{1}{5}n^2\right)\left(\frac{2}{3}-\frac{1}{5}n^2\right)}[/tex]
Step-by-step explanation:
[tex]\mathrm{\frac{4}{9}-\frac{1}{25}n^4}\\\\\mathrm{=\left(\frac{2}{3}\right)^2-\left(\frac{1}{5}n^2\right)^2}\\\\\mathrm{=\left(\frac{2}{3}+\frac{1}{5}n^2\right)\left(\frac{2}{3}-\frac{1}{5}n^2\right)}[/tex]