Answer:

• What is the molecular weight of a gas which diffuses 1/25 as fast as hydrogen?25
• Solution:
• Solution:1) Set rates and molecular weights:
• Solution:1) Set rates and molecular weights:rate1 = unknown gas = 1
• Solution:1) Set rates and molecular weights:rate1 = unknown gas = 1rate2 = H2 = 25
• Remember, 1/25th of 25 is 1.
• is 1.The molecular weight of H2 = 2.016
• is 1.The molecular weight of H2 = 2.016The molecular weight of the other gas = x.
• is 1.The molecular weight of H2 = 2.016The molecular weight of the other gas = x.2) By Graham's Law (see the solution to problem #1), we have:
• is 1.The molecular weight of H2 = 2.016The molecular weight of the other gas = x.2) By Graham's Law (see the solution to problem #1), we have:1 / 25 = 2.016 / x
• = 2.016 / x0.0004 = 2.016 / (x remember to square both sides)
• x = 2520 g/molecular

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