Answer: -10
Explanation:
according to the given question , we know that the mirror formula is
1/f = 1/v + 1/u ---------(1)
where f → focal length = -20 cm
v → image distance
u→object distance
now, according to the given question
hi / ho = - V/U = 2
⇒ hi = 2ho also v = -2u
since we got v = -2u -----(2)
now by substituting equation (2) in (1) gives
⇒ -1/20 = -1/2u + 1/u
⇒ -1/20 = -1 + 2 / 2u
⇒ -1/20 = 1/2u
⇒ 2u = - 20
⇒ u = -10 cm
Answer:
Solution
verified
Verified by Toppr
Correct option is A)
The focal length of the mirror is 20cm.
In the case of real image,
The object distance is u
1
, then the image distance will be −2u
.
The mirror formula is given as,
v
+
u
=
f
−2u
−
20
−1
=30cm
In the case of virtual image,
The object distance is −u
2
, then the image distance will be 2u
2u
−u
=10cm
The distance between two positions of object is given as,
u=30−10
=20cm
Thus the distance between the two positions of object is 20cm.
thanks for this .....❤️
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Answers & Comments
Answer: -10
Explanation:
according to the given question , we know that the mirror formula is
1/f = 1/v + 1/u ---------(1)
where f → focal length = -20 cm
v → image distance
u→object distance
now, according to the given question
hi / ho = - V/U = 2
⇒ hi = 2ho also v = -2u
since we got v = -2u -----(2)
now by substituting equation (2) in (1) gives
⇒ -1/20 = -1/2u + 1/u
⇒ -1/20 = -1 + 2 / 2u
⇒ -1/20 = 1/2u
⇒ 2u = - 20
⇒ u = -10 cm
Verified answer
Answer:
Solution
verified
Verified by Toppr
Correct option is A)
The focal length of the mirror is 20cm.
In the case of real image,
The object distance is u
1
, then the image distance will be −2u
1
.
The mirror formula is given as,
v
1
+
u
1
=
f
1
−2u
1
1
−
u
1
1
=
20
−1
u
1
=30cm
In the case of virtual image,
The object distance is −u
2
, then the image distance will be 2u
2
.
The mirror formula is given as,
v
1
+
u
1
=
f
1
2u
1
1
+
−u
1
1
=
20
−1
u
2
=10cm
The distance between two positions of object is given as,
u=30−10
=20cm
Thus the distance between the two positions of object is 20cm.
thanks for this .....❤️