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pavan1012
@pavan1012
June 2021
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2,3 answer its urgent
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kvnmurty
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2) simple interest: I = P r t/100 = P * r/100 * (8 1/3) = P r /12
sum = P + P r t = P [ 1 + r/12 ] = 2 * P given
so r / 12 = 1 => r = 12 %
compound interest: sum = P (1 + r/100)^t = 2 P given
(1 + r/100)^(25/3) = 2
25/3 * Log (1+ r/100) = Log 2
Log (1 + r/100) = 3/25 * Log 2 = 0.0361
1 + r/100 = 1.08673
r = 100 * 0.08673 = 8.673%
3) 5% of $ 9, 000 = 5 /100 * 9000 = 450 $
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Answers & Comments
Verified answer
2) simple interest: I = P r t/100 = P * r/100 * (8 1/3) = P r /12sum = P + P r t = P [ 1 + r/12 ] = 2 * P given
so r / 12 = 1 => r = 12 %
compound interest: sum = P (1 + r/100)^t = 2 P given
(1 + r/100)^(25/3) = 2
25/3 * Log (1+ r/100) = Log 2
Log (1 + r/100) = 3/25 * Log 2 = 0.0361
1 + r/100 = 1.08673
r = 100 * 0.08673 = 8.673%
3) 5% of $ 9, 000 = 5 /100 * 9000 = 450 $