D. (31.5x - 2) cm
GIVEN THAT,
The sides of rectangle are of length (3x + 1) cm and (x - 2) cm
★Longer side will be Length and Smaller side will be Breadth of rectangle
=> Length of Rectangle = (3x + 1) cm
=> Breadth of Rectangle = (x - 2) cm
And,
Area of Rectangle = 2 cm²
Length×Breadth = 2
(3x + 1) × (x - 2)= 2
= 1176x²+3x+2x+1 = 1176x²+5x+1-2
= 06x²+5x-116 = 06x²+29x-24x-116
= 0x(6x+29)-4(6x+29) = 0(x-4)(6x+29)
= 0=> x = 4 or x = -29/6=> x
= 4[ Length and breadth cannot be negative ]
=> Length = 3x+1 = 3(4)+1 = 12+1
Length, L = 13 cm=> Breadth
= 2x+1 = 2(4)+1 = 8+1Breadth, B = 2 cm² Now,Perimeter of Rectangle = 2(L+B)= 2(13+9)= 2×22= 44 cm
(31.5x - 2) or (3x²−5−2) cm
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Answer:
D. (31.5x - 2) cm
Explanation:
GIVEN THAT,
The sides of rectangle are of length (3x + 1) cm and (x - 2) cm
★Longer side will be Length and Smaller side will be Breadth of rectangle
=> Length of Rectangle = (3x + 1) cm
=> Breadth of Rectangle = (x - 2) cm
And,
Area of Rectangle = 2 cm²
Length×Breadth = 2
(3x + 1) × (x - 2)= 2
= 1176x²+3x+2x+1 = 1176x²+5x+1-2
= 06x²+5x-116 = 06x²+29x-24x-116
= 0x(6x+29)-4(6x+29) = 0(x-4)(6x+29)
= 0=> x = 4 or x = -29/6=> x
= 4[ Length and breadth cannot be negative ]
=> Length = 3x+1 = 3(4)+1 = 12+1
Length, L = 13 cm=> Breadth
= 2x+1 = 2(4)+1 = 8+1Breadth, B = 2 cm² Now,Perimeter of Rectangle = 2(L+B)= 2(13+9)= 2×22= 44 cm
Answer:
(31.5x - 2) or (3x²−5−2) cm
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