Answer:

Here is the answer:

(4, - 1)

Solution:

Using the elimination method:

y = x—5

y= -x + 3

_______

2y=-2

y=-1

Input the value of y into one of the equations:

(You can use any of the two equations, it would yield the same result.)

y=x-5

-1=x-5

x=4

In the other one,

y=-x+3

-1=-x+3

x=4

Using the substitution method:

(You can start with any of the equations given. But keep in mind that in the next procedure, you will need to input the value in the other one. After that, you will go back and input the value to the one where you started off. )

y=x-5

=>x=y+5

y=-x+3

=>x=-y+3

Let us use the value of x in the first equation and input to the x of the second one:

x=-y+3

y+5=-y+3

2y=-5+3

2y=-2

y=-1

Then we put the value of y to the first one:

x=-1+5

x=4

Type of Solution: Unique Solution

I hope this helps! (I'll type the next one.)

Edit for the third number:

Answer for y=2x-3 and y=2x+4: There is no solution.

Solution:

Using the elimination method:

y=2x-3

(y=2x+4)-1

______

y=2x-3

-y=-2x-4

______

0=-7

(No solution)

Using the substitution method:

y=2x-3

=>2x=y+3 (you can either divide it by 2 or leave it as it is because the term 2x is also used for the other one)

y=2x+4

=>2x=y-4

y+3=y-4

0=-1

(No solution)

Type of Solution:No Solution

I hope this helps!