Answer:

3x−5≤x−2

x∈(−∞,3/2]

x∈[−9/2,3/2]

3x−5≤x−2e3x+7

x−2≤3x+7

2x+9≥0

x≥−9/2

x∈[−9/2,+∞)

hope it's helpful for you ✌️ ✌️

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lene ke liya..

kuch bhi answer mat do thik..