Step-by-step explanation:

Given,

cotθ=

3

1

⇒cotθ=cot60

o

⇒θ=60

o

∴(

2−sin

2

θ

1−cos

2

θ

)

Putting the value of θ we get,

=

2−sin

2

60

o

1−cos

2

60

o

=

2−(

2

3

)

2

1−(

2

1

)

2

=

2−

4

3

1−

4

1

=

4

8−3

4

4−1

=

4

5

4

3

=

5

3

.

. solution. cot x = 1√3 x = 60 degrees cos (x) = cos 60 = 12 sin x = sin 60 = √32 1 - cos² x = 1 ...