Answer:
0.2 mol sample of hydrocarbon, C
X
H
Y
yields after complete combustion with excess O
2
gas, 0.8 mol of CO
and 1.0 mol of H
O. Hence, the hydrocarbon is :
C4H10
Answer
The balanced reaction is as follows:
C
+[X+
4
]O
→XCO
+
O
0.2 excess 0.2X
0.2Y
(Moles before reaction)
Therefore, 0.2X=0.8 and
0.2
=1.0
X=4 and Y=10
Hence, the gas is C
10
.
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Answers & Comments
Answer:
0.2 mol sample of hydrocarbon, C
X
H
Y
yields after complete combustion with excess O
2
gas, 0.8 mol of CO
2
and 1.0 mol of H
2
O. Hence, the hydrocarbon is :
C4H10
Answer:
Answer
The balanced reaction is as follows:
C
X
H
Y
+[X+
4
Y
]O
2
→XCO
2
+
2
Y
H
2
O
0.2 excess 0.2X
2
0.2Y
(Moles before reaction)
Therefore, 0.2X=0.8 and
Y
0.2
=1.0
X=4 and Y=10
Hence, the gas is C
4
H
10
.