r = 49/7
r = 7
Sum = 1st term(1 - r^n) / 1-r
Sum = 1 ( 1 - 7^10) / 1 - 7
Sum = -282475248 / -6
Sum = 47 079 208
1st = 1
2nd = 1(7) = 7
3rd = 7(7) = 49
4th = 49(7) = 343
5th = 343(7) = 2401
6th = 2401(7) = 16807
7th = 16807(7) = 117649
8th = 117679(7) = 823543
9th = 823543(7) = 5764801
10th = 5764801(7) = 40353607
Sum = 1 + 7 + 49 + 343 + 2401 + 16807 + 117649 + 823543 + 5764801 + 40353607
The sum is 47 079 208
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Answers & Comments
What is the sum of the first 10 of the geometric sequence 1, 7, 49,
Solution:
r = 49/7
r = 7
Sum = 1st term(1 - r^n) / 1-r
Sum = 1 ( 1 - 7^10) / 1 - 7
Sum = -282475248 / -6
Sum = 47 079 208
Checking:
1st = 1
2nd = 1(7) = 7
3rd = 7(7) = 49
4th = 49(7) = 343
5th = 343(7) = 2401
6th = 2401(7) = 16807
7th = 16807(7) = 117649
8th = 117679(7) = 823543
9th = 823543(7) = 5764801
10th = 5764801(7) = 40353607
Sum = 1 + 7 + 49 + 343 + 2401 + 16807 + 117649 + 823543 + 5764801 + 40353607
Sum = 47 079 208
Answer:
The sum is 47 079 208
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