2. two buses left the terminal at the same. Bus A travels to the east, whole Bus B travels to the west after 4 hours, the buses are 520km apart. If bus A travels 15 kph faster than Bus B, find the average speed for each bus
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Let's call the speed of Bus B "x" km/h, then the speed of Bus A would be "x + 15" km/h.
We know that the buses are moving away from each other, so we can add their speeds together to get the total distance they are traveling per hour:
x + (x + 15) = 2x + 15 km/h
After 4 hours, the buses are 520 km apart, so we can set up the following equation:
distance = rate × time 520 = (2x + 15) × 4
Simplifying the equation:
520 = 8x + 60
Subtracting 60 from both sides:
460 = 8x
Dividing by 8:
x = 57.5
So Bus B is traveling at 57.5 km/h, and Bus A is traveling at 72.5 km/h (57.5 + 15).
Therefore, the average speed of Bus B is 57.5 km/h, and the average speed of Bus A is 72.5 km/h.