Step-by-step explanation:

a+b+c =4

a²+b²+c²= 55/2

now,

a+b+c= 4

on sq. both side

(a+b+c)²= 4²

a²+b²+c²+2(ab+bc+ca) = 16

55/2 +2(ab+bc+ca) = 16

2(ab+bc+ca)= 16 -55/2

2(ab+bc+ca)= -23/2

ab+bc+ca= -23/4

a³+b³+c³-3abc= (a+b+c)(a²+b²+c²-(ab+bc+ca)}

= (4){55/2- (-23/4)}

= 4{55/2 +23/4}

= 4(133/4)

= 133

#666

Answer:

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