Given this set of quantum numbers for a multi-electron atom 2, 0, 0, and -1/2. The next higher allowed set of n and I for this atom in its ground state 1) n=2, 1=0 3) n=3, 1=0 2) n=2, 1=1 4) n=3, 1=1
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Verified answer
ANSWER :
Correct option is 2nd one)
Given a set of quantum numbers, n=2,l=0 for a multi-electron atom refers to 2s orbital.
The next higher allowed set of 'n' and 'l' quantum numbers for this atom in the ground state is n=2,l=1. This corresponds to 2p orbital.
Note: The orbital with a higher value of the sum (n+l) has higher energy.
For 2s orbital (n+l)=(2+0)=2
For 2p orbital (n+l)=(2+1)=3
Hence, the correct option is 2.
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