2. The length of a rectangular parking lot is 36 m longer than its width. The area of the parking lot is 5,152m²
a.How would you represent the width of the parking lot? How about its length? d. What is the length of the parking lot? How about its width? Explain how you arri vour answer.
a.How would you represent the width of the parking lot? How about its length? d. What is the length of the parking lot? How about its width? Explain how you arri vour answer.
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Answer:
width=56m
length=36m
Step-by-step explanation:
A= lw = (w+36)(w) = 5152
w^2+36w = 5152w
2
+36w=5152
w^2 +36w-5152=0w
2
+36w−5152=0
(w+92)(w-56)=0(w+92)(w−56)=0
w+92= 0w+92=0 or w-56 = 0w−56=0
w=-92w=−92 or w=56w=56
We discard the value w=-92 because lengths can't be negative.
Therefore,
width=56m
length= 36