2. The length of a rectangle is 1 m more than twice the width. The perimeter of the rectangle is 26m. Find the length and width of the rectangle.
a. Solve the problem by showing the process step by step.
b. What property did you use?
ASAP PLS.
a. Solve the problem by showing the process step by step.
b. What property did you use?
ASAP PLS.
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Answer:
2x + 1
2x = 1
2 2
x = 1 (value of x)
2
P = 2L + 2W
26 = 2(2x + 1) + 2w
26 = 2(2(0.5) + 1 ) + 2w
26 = 2(2) + 2w
26 = 4 + 2w
26 - 4 = 2w
22 = 2w
2 2
w = 11(Width)
26 = 2L + 2(11)
26 = 2L + 22
26 - 22 = 2L
4 = 2L
2 2
L = 2 (Length)
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