Verified answer

Given :-

☛ Inner Diameter of a Circular well = 3.5 m, then it's radius will be 1.75 m.

☛ Height of Circular well = 10 m.

To Find :-

☛ It's Inner Curved Surface Area

☛ The cost of plastering this curved surface at the rate of 40 per m².

Formula Used Here :-

➛ Curved Surface Area of Cylinder= 2πrh

Solution :-

Curved Surface Area of Cylinder= 2πrh

[tex] = > C.S.A \: of \: cylinder \: = 2 \times \frac{22}{7} \times 1.75 \times 10 \\ \\ = > C.S.A \: of \: cylinder \: = 2 \times \frac{22}{\cancel {7}} \times \cancel {1.75} \times 10 \\ \\ = > C.S.A \: of \: cylinder \: = 2 \times 22 \times 0.25 \times 10 \\ \\ = > C.S.A \: of \: cylinder \: = 44 \times 2.5 \\ \\ = > C.S.A \: of \: cylinder \: = 110 \: {m}^{2} [/tex]

Hence, C.S.A of Cylinder is 110 m².

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➥ The cost of plastering this curved surface at the rate of 40 per m².

Cost of 1 m² plastering = ₹ 40

Cost of 110 m² plastering = 110 m² × ₹ 40

Cost of 110 m² plastering = ₹ 4400

Therefore,

➜C.S.A of Cylinder is 110 m².

➜Cost of 110 m² plastering = ₹ 4400

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