To find the number of 3-digit numbers between 99 and 3,000 where the tens place is 7, we need to consider two scenarios:
1. The hundreds place is less than 7:
In this case, the hundreds place can be any digit from 1 to 9 (excluding 7), the tens place is fixed at 7, and the units place can be any digit from 0 to 9. So, we have 9 choices for the hundreds place, 1 choice for the tens place, and 10 choices for the units place, resulting in a total of 9 * 1 * 10 = 90 numbers.
2. The hundreds place is equal to 7:
In this case, the hundreds place is fixed at 7, the tens place is fixed at 7, and the units place can be any digit from 0 to 9. So, we have 1 choice for the hundreds place, 1 choice for the tens place, and 10 choices for the units place, resulting in a total of 1 * 1 * 10 = 10 numbers.
Therefore, the total number of 3-digit numbers between 99 and 3,000 where the tens place is 7 is 90 + 10 = 100.
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Answer:
To find the number of 3-digit numbers between 99 and 3,000 where the tens place is 7, we need to consider two scenarios:
1. The hundreds place is less than 7:
In this case, the hundreds place can be any digit from 1 to 9 (excluding 7), the tens place is fixed at 7, and the units place can be any digit from 0 to 9. So, we have 9 choices for the hundreds place, 1 choice for the tens place, and 10 choices for the units place, resulting in a total of 9 * 1 * 10 = 90 numbers.
2. The hundreds place is equal to 7:
In this case, the hundreds place is fixed at 7, the tens place is fixed at 7, and the units place can be any digit from 0 to 9. So, we have 1 choice for the hundreds place, 1 choice for the tens place, and 10 choices for the units place, resulting in a total of 1 * 1 * 10 = 10 numbers.
Therefore, the total number of 3-digit numbers between 99 and 3,000 where the tens place is 7 is 90 + 10 = 100.
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Answer:
900 three digit numbers
Therefore there are 900 three digit numbers.
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