.2) The binding energy of a satellite revolving around planet in a circular orbit is 6 x 10° J. Its kinetic energy is a) 12 x 10°J
b) - 12 x 109 J
c) 6 x 10° J
d) - 6 x 10° J
b) - 12 x 109 J
c) 6 x 10° J
d) - 6 x 10° J
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Answers & Comments
Explanation:-
Binding energy of the satellite to move in a circular orbit,E=6×10° J
We know, kinetic energy of a revolving satellite in a circular orbit is, K=GMm/2r
Potential energy, PE= -GMm/r
∴Total energy, E= -GMm/2r
as, total energy ,|E| = BINDING ENERGY
∴K.E=B.E
→K.E= 6×10° J
∴OPTION C is correct