Answer:

C2H6O2

Explaination:

Solution:

Given Atomic weight Smallest quotient

C=1.388g ÷12g/mol=0.1156mol÷0.1156=1

H=0.345g÷ 1g/mol=0.345mol÷0.1156=3

O=1.850g÷16g/mol=0.1156mol÷0.1156=1

Empirical formula is CH3O

The mass of the empirical formula is:

Atomic weight

C=1mol×12g/mol=12g

H=3mol× 1g/mol= 3g

O=1mol×16g/mol=16g

=31g

molecular weight of the compound 62g

______________________________ = 2 multiples

empirical formula mass 31g

2(CH3O) 2×1C=C2

2×3H=H6

2×1O=O2

Therefore, the molecular formula is C2H6O2