One number is 4 less than another number. If their sum is 100, find the numbers.
Let x and y = 2 numbers
one number is 4 less than another number = x = y + 4 → equation 1
x + y = 100 → equation 2
(y + 4) + y = 100
1/2(2y + 4 = 100)
y + 2 = 50
y = 50 - 2
y = 48
x = y + 4
x = 48 + 4
x = 52
The numbers are 52 and 48.
let x = another number
x - 4 = one number
sum of 2 numbers = (x-4) + x = 100
2x - 4 = 100
2x = 100 + 4
2x = 104
52 - 4 = 48
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Answers & Comments
Question:
One number is 4 less than another number. If their sum is 100, find the numbers.
Solution:
Let x and y = 2 numbers
one number is 4 less than another number = x = y + 4 → equation 1
x + y = 100 → equation 2
(y + 4) + y = 100
1/2(2y + 4 = 100)
y + 2 = 50
y = 50 - 2
y = 48
x = y + 4
x = 48 + 4
x = 52
Answer:
The numbers are 52 and 48.
Another way to solve:
let x = another number
x - 4 = one number
sum of 2 numbers = (x-4) + x = 100
2x - 4 = 100
2x = 100 + 4
2x = 104
x = 52
x - 4 = one number
52 - 4 = 48
The numbers are 52 and 48.
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