Let's call the original number of cows the villager had "X." In 2011, 10 cows died, so the villager had X - 10 cows remaining. In 2012, 25/2 of the remaining cows died, which means (25/2)*(X - 10) cows died. So, the number of cows remaining after 2012 would be (X - 10) - (25/2)*(X - 10).
Given that the remaining cows are 63 after 2012, we can set up the equation:
(X - 10) - (25/2)*(X - 10) = 63
Now, you can solve for X:
(X - 10) - (25/2)*(X - 10) = 63
Multiply both sides by 2 to get rid of the fraction:
Answers & Comments
Answer:
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Step-by-step explanation:
Correct option is B)
Let the total number is x.
Then, (
100−25
) of (
100−10
)%x=4050
⇒75% of 90% of x=4050
⇒
100
75
×
100
90
×x=4050
⇒x=
27
4050×50
=6000
Therefore, original inhabitants are 6000
Verified answer
Answer:
Let's call the original number of cows the villager had "X." In 2011, 10 cows died, so the villager had X - 10 cows remaining. In 2012, 25/2 of the remaining cows died, which means (25/2)*(X - 10) cows died. So, the number of cows remaining after 2012 would be (X - 10) - (25/2)*(X - 10).
Given that the remaining cows are 63 after 2012, we can set up the equation:
(X - 10) - (25/2)*(X - 10) = 63
Now, you can solve for X:
(X - 10) - (25/2)*(X - 10) = 63
Multiply both sides by 2 to get rid of the fraction:
2(X - 10) - 25(X - 10) = 126
Distribute the 2 and the -25:
2X - 20 - 25X + 250 = 126
Combine like terms:
-23X + 230 = 126
Subtract 230 from both sides:
-23X = -104
Now, divide by -23:
X = 4
So, the villager originally had 4 cows.
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